Given a regular tetrahedron with volume \(1 \text{cm}^3\) and a cube with volume \(1 \text{cm}^3\), which object has smaller surface area?
Details and Assumptions:
In a regular tetrahedron, all four faces are equilateral triangles, and
In a cube, all six faces are squares.
The perfect slice through a cube will reveal a regular hexagonal cross section. If this is a \(2\text{ in} \times 2\text{ in} \times 2\text{ in}\) cube, what is the surface area of the hexagonal cross section?
The dodecahedron has 12 pentagonal faces. Therefore it has \(\frac{12 \times 5}{2} = 30\) edges.
The icosahedron has 20 equilateral triangular faces. Therefore it has \(\frac{20 \times 3}{2} = 30\) edges.
How many edges does a truncated icosahedron have?
After drawing in the diagonal perforations onto a unit cube, we are left with a geometric shape object. What is the volume of this new object?
A solid has 12 faces and 20 edges. Given that Euler's Formula applies, how many vertices does it have?