Classical Mechanics
# Conservation of Energy

The gravitational acceleration is \( g =10 \text{ m/s}^2. \)

A roller-coaster of mass \( M= 2000 \text{ kg} \) has a speed of \( v_1 = 10 \text{ m/s} \) as it goes over the top of a \(15\)-meter-high hill. Then it goes over a another hill of height \(10\) meters, and at the crest of that hill, the roller-coaster is moving at \( v_2 = 13 \text{ m/s}.\) How much work did friction do on the coaster during its movement between the two hills?

The gravitational acceleration is \( g= 10 \text{ m/s}^2. \)

The gravitational acceleration is \( g = 10 \text{ m/s}^2. \)

An object with mass \( m = 1 \text{ kg} \) at the top of a \( h = 7 \text{ m} \) tall hill starts to go down from rest. The downhill portion of the run is covered with frictionless material but the flat section at the base of the hill has a spot of friction \( 2 \text{ m} \) in length. The object comes straight down the hill, over the spot of friction at the bottom, hits and presses the the damping spring \( 20 \text{ cm} \) in the process. If the spring constant is \( k = 2 \times 10^2 \text{ N/m}, \) what is the magnitude of kinetic friction between the object and flat section.

The gravitational acceleration is \( g = 10 \text{ m/s}^2 \) and air resistance is negligible.

×

Problem Loading...

Note Loading...

Set Loading...