RC circuits (direct current)

         

Find the charge on the capacitor in the circuit shown in the figure, at time t=t=\infty. The capacitance of the capacitor is C=2 F, C= 2 \text{ F}, resistances of resistors are given by R1=2 Ω, R_1 = 2 \ \Omega, R2=2 Ω, R_2 = 2 \ \Omega, and R3=5 Ω R_3 = 5 \ \Omega and the voltage of the ideal battery is given by V=35 V. V= 35 \text{ V}.

Given R1=3.0 Ω, R_1 = 3.0\ \Omega, R2=6.0 Ω, R_2 = 6.0\ \Omega, R3=4.0 Ω, R_3 = 4.0\ \Omega, R4=8.0 Ω. R_4 = 8.0\ \Omega. Find the charge of the capacitor in the circuit shown in the above figure. The capacitance of the capacitor is C=1 F, C= 1 \text{ F}, and the voltage of the ideal battery is given by V=21 V. V= 21 \text{ V}.

Given R1=3.0 Ω, R_1 = 3.0\ \Omega, R2=6.0 Ω, R_2 = 6.0\ \Omega, R3=6.0 Ω, R_3 = 6.0\ \Omega, R4=12.0 Ω, R_4 = 12.0\ \Omega, R5=8.0 Ω, R_5 = 8.0\ \Omega, R6=4.0 Ω, R_6 = 4.0\ \Omega, R7=2.0 Ω R_7 = 2.0\ \Omega and R8=4.0 Ω. R_8 = 4.0\ \Omega. Find the charge of the capacitor in the circuit shown in the figure. The capacitance of the capacitor is C=2 F, C= 2 \text{ F}, and the voltage of the ideal battery is given by V=54 V. V= 54 \text{ V}.

Find the charge of the capacitor in the circuit shown in the figure above. The capacitance of the capacitor is C=4 F, C= 4 \text{ F}, the resistances of the resistors are R1=2 Ω R_1 = 2 \ \Omega and R2=5, Ω R_2 = 5 ,\ \Omega and the voltage of the ideal battery is given by V=35 V. V= 35 \text{ V}.

Given R1=2.0 Ω, R_1 = 2.0\ \Omega, R2=4.0 Ω, R_2 = 4.0\ \Omega, R3=7.0 Ω, R_3 = 7.0\ \Omega, R4=14.0 Ω, R_4 = 14.0\ \Omega, R5=6.0 Ω, R_5 = 6.0\ \Omega, R6=3.0 Ω, R_6 = 3.0\ \Omega, R7=1.0 Ω R_7 = 1.0\ \Omega and R8=2.0 Ω. R_8 = 2.0\ \Omega. Find the charge of the capacitor in the circuit shown in the figure. The capacitance of the capacitor is C=1 F, C= 1 \text{ F}, and the voltage of the ideal battery is given by V=36 V. V= 36 \text{ V}.

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