Geometry
# Solving Triangles

If \(CD=\sqrt{3},\) \(PQ=2,\) and \(\angle PDQ=30^\circ,\) find \(CP.\)

In triangle \(ABC\), \( \angle BAC = 2 \angle ABC \), \( AB= 31, AC = 13 \). What is \(BC^2\)?

If \( AP = AC + 2\cdot CB \), what is the measure \(\angle ABP \) in degrees?

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