Replacing 1, 2, 2015 with x, y, z

Algebra Level 2

If \[\frac{1}{ \color{blue}{x} + 1 } + \frac{2}{ \color{red}{y}+2} + \frac{2015}{\color{green}{z}+2015} = \frac{1}{2},\] what is \[\frac{\color{blue}{x}}{\color{blue}{x}+1} + \frac{\color{red}{y}}{\color{red}{y}+2} + \frac{\color{green}{z}}{\color{green}{z}+2015}?\]

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