Here is my attempt to demonstrate that \(1=0\).

1) \(0=0\)

2) \(0=1-1\)

3) \(n\cdot 0=n(1-1)\), \(n\) is a big natural number.

4) \(0=\underset { n\text{ times} }{ \underbrace { (1-1)+(1-1)+...+(1-1) } } \)

5) \(0=1-1+1-\cdots -1\)

6) \(0=1-(1-1+1-1+\cdots)\)

7) \(0=1-((1-1)+(1-1)+\cdots +(1-1))\)

8) \(0=1-(0+0+\cdots + 0)\)

9) \(0=1\)

In which step is the first error committed?

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