Given that \( 2.004 < \log_{10} 101 < 2.005\), how many digits are there in the decimal representation of \( 101^{101}\)?

**Details and assumptions**

Clarification: The decimal representation of \(2^{10}\) is \(2^{10}=1024\), which has 4 digits.

×

Problem Loading...

Note Loading...

Set Loading...