101 to the 101
Algebra
Level
3
Given that \( 2.004 < \log_{10} 101 < 2.005\), how many digits are there in the decimal representation of \( 101^{101}\)?
Details and assumptions
Clarification: The decimal representation of \(2^{10}\) is \(2^{10}=1024\), which has 4 digits.
by
Calvin Lin