# $$-1=1$$?

Algebra Level 5

I. Start with the famous identity $$e^{iπ}=-1$$.

II. So, $$e^π=(-1)^{1/i}$$.

III. So, $$e^{π/i}=(-1)^{(1/i) \times (1/i)}=(-1)^{-1}=-1$$.

IV. So, $$e^{π/i}=e^{iπ}$$.

V. So, $$π/i=iπ$$ or $$i^2=1$$.

VI. But $$i=\sqrt{-1}$$ or $$i^2=-1$$. So, $$-1=1$$.

In which step is there an error?

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