Here's my attempt at proving that 2=1. In which step did I first commit a flaw in my logic?
122232=1=2+2=3+3+3(2 times)(3 times)
Step 1: For any positive integer:
x2=x+x+⋯+x(x times)
Step 2: Now, differentiating with respect to x:
2x=1+1+⋯+1(x times).
Step 3: Summing this up, we get
2x=x.
Step 4: Dividing by x, we get
2=1.