Do it without diagram!

Geometry Level 5

In triangle \(ABC\) we have \(AB = BC\), \(\angle B = 20^\circ\). Point \(M\) on \(AC\) is such that \(AM : MC = 1 : 2\), point \(H\) is the projection of \(C\) to \(BM\). Find \(\angle AHB\) in degrees.

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