In the following set up the rope is pulled with a Velocity \(V\) and the block of mass \(M\) starts moving horizontally initially and then moves up. Let at \(t = 0\) the block make an angle of \(\phi\) with the vertical. At \(t = t_1\) the block makes an angle of \(\theta\) with the vertical.Given it doesn't move upwards till \(t_1\) find the horizontal velocity at \(t = t_1\).

**Details and Assumptions**:

\(V = 150 \text{ m/s}\)

\(\theta = 30^{\circ}\)

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