16.16

Algebra Level 5

S=n=0(1)nn2016n\large S = \sum_{n=0}^{ \infty } \dfrac{(-1)^n n}{ 2016^n }
Find the value of 1S \left \lfloor \dfrac{1}{S} \right \rfloor .

Notation: \lfloor \cdot \rfloor denotes the floor function.

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