# 169-follower problem

169 is a square and it is a sum of squares ($$169 = 12^2 + 5^2$$).

But its square can also be written as the sum of two squares. Let $\large 169^2 = a^2 + b^2$ with $$a > b > 0$$ and $$\gcd(a,b)=1$$. Without using a calculator, find $$a + b$$.

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