169-follower problemNumber Theory Level 4
169 is a square and it is a sum of squares (\(169 = 12^2 + 5^2\)).
But its square can also be written as the sum of two squares. Let \[\large 169^2 = a^2 + b^2\] with \(a > b > 0\) and \(\gcd(a,b)=1\). Without using a calculator, find \(a + b\).