1729 followers problem (a bit late may be)

Calculus Level 5

$\large\sum_{x=1}^{1729} \left[\Gamma\left(\dfrac{1+2x}{2}\right)\Gamma\left(\dfrac{1-2x}{2}\right)\right]$

Simplify the above summation and give your answer to correct four decimal places.

Clarification: $$[\cdot]$$ does not denote greatest integer function; they are just square brackets. Also, $$\Gamma(n)$$ is the gamma function .

Bonus Question: Find the value of $\displaystyle\sum_{x=1}^{1730} \left[\Gamma\left(\dfrac{1+2x}{2}\right)\Gamma\left(\dfrac{1-2x}{2}\right)\right].$

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