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A particle is projected with velocity v0v_0v0 horizontally from a height HHH over a hill, and strikes the hill perpendicularly.
Find 2gH/v022gH/v_0 ^ 22gH/v02
Assume the hill rises linearly from the origin at an angle θ=π6=30∘\theta = \dfrac\pi6 = \si{30}^\circθ=6π=30∘.
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