Hit The Right Angle

A particle is projected with velocity v0v_0 horizontally from a height HH over a hill, and strikes the hill perpendicularly.

Find 2gH/v022gH/v_0 ^ 2

Assume the hill rises linearly from the origin at an angle θ=π6=30\theta = \dfrac\pi6 = \si{30}^\circ.

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