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Let AAA be the constant term in the expansion of (x+x2+1x+1x2)15 {\left(x+x^2+\dfrac{1}{x}+\dfrac{1}{x^2}\right)}^{15}(x+x2+x1+x21)15.
Let BBB be the value of ∑r=05(15r+5)(153r)\displaystyle \sum _{ r=0 }^{ 5 }{ \begin{pmatrix} 15 \\ r+5 \end{pmatrix} } \begin{pmatrix} 15 \\ 3r \end{pmatrix}r=0∑5(15r+5)(153r).
Find the value of 2AB\frac {2 A }{ B } B2A.
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