\[ \int_{0}^{\infty}\sin^{-1}(e^{-x})dx = \dfrac{\pi^{\phi}}{\alpha}\ln(\alpha) \]

The equation above holds true for positive integers \(\phi\) and \(\alpha\) with \(\alpha\) being a prime. Submit \(\alpha^{\alpha}+\phi^{\phi}\).

###### Try a bit harder version here.