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Suppose that xxx and yyy are real numbers such that logx3y=2013\log_x 3y = \frac{20}{13}logx3y=1320 and log3xy=23\log_{3x}y=\frac23log3xy=32. The value of log3x3y\log_{3x}3ylog3x3y can be expressed in the form ab\frac abba where aaa and bbb are positive relatively prime integers. Find a+ba+ba+b.
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