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limn→∞n1999nx−(n−1)x=12000,x= ?\large \lim _{ n\rightarrow \infty }{ \frac { { n }^{ 1999 } }{ { n }^{ x }-{ (n-1) }^{ x } } =\frac { 1 }{ 2000 } }, \quad x= \, ? n→∞limnx−(n−1)xn1999=20001,x=?
Clarification: Take xxx as a constant.
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