Forgot password? New user? Sign up
Existing user? Log in
limn→∞n1999nx−(n−1)x=12000,x= ?\large \lim _{ n\rightarrow \infty }{ \frac { { n }^{ 1999 } }{ { n }^{ x }-{ (n-1) }^{ x } } =\frac { 1 }{ 2000 } }, \quad x= \, ? n→∞limnx−(n−1)xn1999=20001,x=?
Clarification: Take xxx as a constant.
Problem Loading...
Note Loading...
Set Loading...
