#2015_26 Learning Calculus!
Calculus
Level
2
\[\large \lim _{ n\rightarrow \infty }{ \frac { { n }^{ 1999 } }{ { n }^{ x }-{ (n-1) }^{ x } } =\frac { 1 }{ 2000 } }, \quad x= \, ? \]
Clarification: Take \(x\) as a constant.
by
Anandhu Raj