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#2015_26 Learning Calculus!

limnn1999nx(n1)x=12000,x=?\large \lim _{ n\rightarrow \infty }{ \frac { { n }^{ 1999 } }{ { n }^{ x }-{ (n-1) }^{ x } } =\frac { 1 }{ 2000 } }, \quad x= \, ?

Clarification: Take xx as a constant.

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