#2015_9 This is time for JEE Advanced..

Sum to (n+1)(n+1) terms of the series,

C02C13+C24C35+...\frac { { C }_{ 0 } }{ 2 } -\frac { { C }_{ 1 } }{ 3 } +\frac { { C }_{ 2 } }{ 4 } -\frac { { C }_{ 3 } }{ 5 } +... is,

Note: Cr=(nr){ C }_{ r }=\left( \begin{matrix} n \\ r \end{matrix} \right)

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