# 3, 2, 1, Go!

$\large { {2016 \, 2015 \, 2014 \ldots 4 \, 3 \, 2 \, 1} }$

The above expression shows the concatenation of the first $$2016$$ positive integers written backwards.

Let $$L$$ and $$S$$ denote the number of digits and the sum of digits, respectively, of this large number. Compute $\dfrac1{10} \left[ (S-L) \pmod{2016} \right].$

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