\({3}^2{39}^{4}={3}^\alpha \cdot p^\beta\)

Algebra Level 1

If \[ {3}^2{39}^{4}={3}^\alpha \cdot p^\beta,\] where \(p\) is prime number, what is \(p+\alpha+\beta?\)

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Ajay Dutta by Ajay Dutta
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