#35 Measure Your Calibre

Calculus Level 4

Let α,βR\alpha , \beta \in \mathbb R be such that limx0x2sin(βx)αxsinx=1\displaystyle{\lim_{x \rightarrow 0} \dfrac{x^2 \sin(\beta x)}{\alpha x - \sin x} = 1}. Then 6(α+β)+2=?6(\alpha + \beta)+2= ?

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