Forgot password? New user? Sign up
Existing user? Log in
L=limx→πtan(πcos2x)(x−π)2\large L = \lim_{x \to \pi} \frac{\tan(\pi \cos^2x)}{(x-\pi)^2} L=x→πlim(x−π)2tan(πcos2x).
Find Lπ\dfrac{L}{\pi}πL
Problem Loading...
Note Loading...
Set Loading...