45 degrees below the ground II

A projectile is thrown horizontally from a 20 m20\text{ m} building. If, at the landing point, the velocity vector of the projectile makes an angle of 4545^\circ below the ground, calculate the projectile's initial speed in m/s\text{m/s}.

Take gg (the accelaration due to gravity) as 10 m/s210 \text{ m/s}^2.

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