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Let f(x)=12+22+32+⋯+(x−1)2+x2f(x) = \sqrt{1^{2} + 2^{2} + 3^{2} + \cdots + (x-1)^{2} + x^{2}} f(x)=12+22+32+⋯+(x−1)2+x2.
Find the minimum value of n≥2n \geq2n≥2 such that f(n)f(n)f(n) is a positive integer.
nnn is a positive integer.
Clarification: f(x)f(x)f(x) denote the square root of the sum of the squares of first xxx positive integers.
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