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limα→0ecos(αn)−eαm=−e2\large \lim_{\alpha\rightarrow 0}\frac{e^{\cos(\alpha^{n})}-e}{\alpha^{m}} = -\frac{e}{2} α→0limαmecos(αn)−e=−2e
Let mmm and nnn be two constant positive integers greater than 1 such that the equation above holds true.
Find the ratio mn \frac{m}{n} nm.
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