**Fact:**

For all numbers \(x\), \[x^{2}-1=(x+1)\times(x-1)\]

Five collegiate math students are discussing this subject:

**Alice:** "Since \(x^{2}-1\) is a product of 2 numbers, all positive integers 1 less than a perfect square are composite."

**Ben:** "All integers 1 more than a perfect square are prime."

**Charlie:** "The lowest possible value for \(x^{2}-1\), where \(x\) is *any* number, is \(-1\)."

**Drake:** "None of you are correct."

**Emily:** "To build off of what Drake said, all of you are wrong because the equation itself is wrong."

Which student is correct?

**For clarity**: When the term, "number," is stated, it means any number that can be found in the complex plane.

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