The position of a particle is given by \( p(t) = -t^2 + 4t \). Its journey starts at \( t= 0 \) and ends when it hits the \( x \) axis again.

At what point in time \( T \) will the particle have completed \( 75 \)% of its path (meaning 75% of the distance in the whole path is traveled by the particle)? Enter \( \left \lfloor 1000 T \right \rfloor \) as your answer.

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