Forgot password? New user? Sign up
Existing user? Log in
limx→0x−sinxx3\displaystyle\lim _{ x\rightarrow 0 }{ \frac { x-\sin { x } }{ { x }^{ 3 } } } x→0limx3x−sinx
is in the form AB!\frac{A}{B!}B!A
where A,BA,BA,B are positive coprime integers
then find A+BA+BA+B
Problem Loading...
Note Loading...
Set Loading...