A calculus problem by Kumar Mayank
Calculus
Level
2
\[ \dfrac12 - \dfrac16 + \dfrac1{24} - \dfrac1{120} + \cdots = \, ? \]
Note that \(6 = 2\times 3, 24 = 2\times3\times4, 120 = 2\times3\times4\times5, \cdots \).
\[ \] Clarification: \(e\) denotes Euler's number, \(e \approx 2.71828\).
by
Kumar Mayank