A calculus problem by Kumar Mayank

Calculus Level 2

\[ \dfrac12 - \dfrac16 + \dfrac1{24} - \dfrac1{120} + \cdots = \, ? \]

Note that \(6 = 2\times 3, 24 = 2\times3\times4, 120 = 2\times3\times4\times5, \cdots \).

\[ \] Clarification: \(e\) denotes Euler's number, \(e \approx 2.71828\).

×

Problem Loading...

Note Loading...

Set Loading...