A calculus problem by Kumar Mayank

Calculus Level 2

12−16+124−1120+⋯= ? \dfrac12 - \dfrac16 + \dfrac1{24} - \dfrac1{120} + \cdots = \, ?

Note that 6=2×3,24=2×3×4,120=2×3×4×5,⋯6 = 2\times 3, 24 = 2\times3\times4, 120 = 2\times3\times4\times5, \cdots .

Clarification: ee denotes Euler's number, e≈2.71828e \approx 2.71828.

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Kumar Mayank by Kumar Mayank
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