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limx→1(1+x2+x)1−x1−x=abn\large \lim_{x \to 1} \left(\frac{1+x}{2+x} \right)^{\frac{1-\sqrt x}{1-x}} = \sqrt[n]{\frac{a}{b}}x→1lim(2+x1+x)1−x1−x=nba
The equation above holds true for positive integers aaa, bbb and nnn, with aaa and bbb being primes. Find the value of a+b+na+b+na+b+n.
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