# So, that's why they love cricket

In a cricket match, a pace bowler $$2\text{ m}$$ tall throws a yorker ball with a horizontal velocity of $$20\text{ m/s}$$. The batsmen hits the ball with twice the horizontal velocity thrown by the bowler at an angle of $${45}^\circ$$ with the horizontal. The ball lands just in front of a fielder who kicked the ball with his foot at an angle of $${30}^\circ$$ with the horizontal in such a way that it landed just in front of the foot of the bowler. Find the velocity with which the fielder kicked the ball.

Details and assumptions:

• Assume the air friction to be negligible.
• Assume that the position of the batsman, bowler and fielder are collinear and the batsman hits the ball in the collinear line.
• Assume that the bowler throws the ball by stretching his hand just above the top of his head.
• Assume that the bowler does not move fom his position after releasing the ball from the crease line.
• Take $$g$$ (acceleration due to gravity) as $$10{\text{m/s}}^2$$.
• Round your answer (in $$\text{m/s}$$) off to the nearest integer.
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