Gravity Escape velocity

ve=2GMr\large v_e = \sqrt{\frac {2GM}r}

A body is projected upwards with a with a velocity equal to 34\frac 34 the escape velocity of Earth vev_e. What is the height it reaches above the surface of the Earth? You will get an answer in the form of aRb\dfrac{aR}{b}. Provide the answer as a+ba + b.

For more such problems, try my set Gravity

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