\[\large v_e = \sqrt{\frac {2GM}r}\]

A body is projected upwards with a with a velocity equal to \(\frac 34\) the escape velocity of Earth \(v_e\). What is the height it reaches above the surface of the Earth? You will get an answer in the form of \(\dfrac{aR}{b}\). Provide the answer as \(a + b\).

For more such problems, try my set Gravity

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