What is the imaginary part of \(\sqrt{-169}\)?

**Details and assumptions**

If a complex number \(z\) is equal to \(a + bi\) where \(a\) and \(b\) are real numbers and \(i^2 = -1\) is the imaginary unit, then the imaginary part of \(z\) is \(b\) (not \(bi\)).

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