A function and its inverse walked into a bar!

Calculus Level 4

Suppose a function f(x)f(x) has an inverse, call it g(x)g(x).

If f(3)=4,f(3)=253f(3) = 4, f'(3) = \sqrt[3]{\dfrac{2}{5}} and f(3)=47f''(3) = -\dfrac{4}{7},

then g(4)=abg''(4) = \dfrac{a}{b}, where aa and bb are positive coprime integers.

Find a+ba + b.

×

Problem Loading...

Note Loading...

Set Loading...