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{acosx+bsinx=3asinx−bcosx=4\large \begin{cases} a\cos x +b\sin x =3 \\ a \sin x- b\cos x=4 \end{cases} ⎩⎨⎧acosx+bsinx=3asinx−bcosx=4 Given the above, find a2+b2a^2+b^2a2+b2.
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