# A geometry problem by rounak chatterjee

Geometry Level 2

if $$p_{1}$$ ,$$p_{2}$$ , $$p_{3}$$denotes the distance of the plane 2x - 3y + 4z+2=0 from the planes 2x - 3y + 4z + 6=0 ;4x - 6y + 8z + 3=0 and 2x - 3y + 4z - 6=0 respectively then,

1. $$p_{1}$$ + 8 $$p_{2}$$ - $$p_{3}$$=0
2. $$p_{3}$$ = 16 $$p_{2}$$
3. 8 $$p_{2}$$= $$p_{1}$$
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