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{x+y=03x+y−4=0x+3y−4=0 \large \begin{cases}{ x + y = 0 } \\ {3x + y - 4 = 0 } \\ {x + 3y - 4= 0 } \end{cases} ⎩⎪⎪⎨⎪⎪⎧x+y=03x+y−4=0x+3y−4=0
The intersection points of these straight lines form a triangle. What kind of triangle is this?
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