# A geometry problem by swapnil rajawat

Geometry Level pending

The equation of the transverse and conjugate axes of a hyperbola are respectively x+2y-3=0, 2x-y+4=0, and there respective length are sqrt 2 and 2/sqrt 3. The equation of the hyperbola 2/5(2x-y+4)^2-3/5(x+2y-3)^2=b. Then find b and pls post solution also.

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