A Huge Summation it is. #3

Number Theory Level 4

∑n=19(11×n)11×n\color{#3D99F6}{\displaystyle \sum_{n=1}^9 \left( {11 \times n} \right)^{11 \times n}}

Find the last three digits of the above summation.

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Sandeep Bhardwaj by Sandeep Bhardwaj
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