A charged particle of charge \(^+\!q\) and mass \(m\) is moving from infinity towards a charge \(^+\!Q\) with a velocity \(v\). The particle is eventually deflected due to the repulsion force in accordance with Coulomb's law.

Given the impact parameter \(b\), find the scattering angle, \(\theta\), in degrees.

**Details and Assumptions**

- Assume that this system is in isolated gravity free space.
- The charge \(^+\!Q\) is fixed.
- Only Coulombic forces are present.
- Impact parameter is the distance between the line of incidence and the fixed charge.
- Scattering angle is the angle made by terminal velocity with initial velocity.
- Take \(q=1.0\,e \), \(~Q=6.0\,e\), \(m = 1.67\times10^{-26}\text{ kg}\), \(v = 1089\text{ ms}^{-1}, b = 57\text{ nm}\).
- \(e\) is elementary positive charge.

×

Problem Loading...

Note Loading...

Set Loading...