A meeting of number family

Logic Level 4

Find the smallest 5-digit-integer $$N$$ so that $$2N$$ is also a 5-digit-integer and all digits $$0, 1, 2, 3,\ldots,9$$ contain in both $$N$$ and $$2N$$.

Note: Each number, $$N$$ and $$2N$$ must contain 5 distinct digits and all the digits in $$N$$ must different from those in $$2N$$.

This problem is a problem in USAMTS (USA Mathematical Talent Search) contest.
×

Problem Loading...

Note Loading...

Set Loading...