4, 3, 2, 1: Part 2
Calculus
Level
4
\[\large \sum _{ n=1 }^{ \infty }{ \dfrac { { n }^{ 2 } }{ 4\cdot { 3 }^{ n }\cdot n! } } =\dfrac { \sqrt [ a ]{ e } }{ b } \]
If the equation above holds true for positive integers, find \(a+b\).
Clarification: \(e \approx 2.71828\) denotes the Euler's number.
by
Jonas Katona