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Let a1=97a_1=97a1=97 and an=nan−1a_n=\dfrac{n}{a_{n-1}}an=an−1n for n>1n > 1n>1. Find a1a2a3a4a5a6a_1a_2a_3a_4a_5a_6a1a2a3a4a5a6.
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