# A problem by Arpita Karkera

Level pending

If $$f\left( x \right) =\frac { { 4 }^{ x } }{ { 4 }^{ x }+2 }$$, then $$\left\lfloor f\left( \frac { 1 }{ 2008 } \right) +f\left( \frac { 2 }{ 2008 } \right) +f\left( \frac { 3 }{ 2008 } \right) +...+f\left( \frac { 2007 }{ 2008 } \right) \right\rfloor -1000$$ is equal to... (where, $$\left\lfloor . \right\rfloor$$ denotes the greatest integer function)

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