A geometry problem by Leonardo Joau

Geometry Level 5

ABCABC is an isosceles triangle with AB=AC\overline{AB}=\overline{AC}.

α\alpha and β\beta are two circumferences that have centres in BC\overline{BC} and intersects this straight line in points BB,SS and CC.

The diameters of α\alpha and β\beta are 2+1\sqrt{2}+1 and 11, respectively.

If BAS=30\measuredangle{BAS}=30^\circ find ABP\angle{ABP}.

Enter your answer in degrees.

Note: Image drawn not up to scale.

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