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ax+by=40ax2+by2=110ax3+by3=310ax4+by4=890 \begin{aligned} ax+by &=& 40 \\ ax^2+by^2 &=& 110 \\ ax^3+by^3 &=& 310 \\ ax^4+by^4 &=& 890 \end{aligned} ax+byax2+by2ax3+by3ax4+by4====40110310890
Let a,b,x,a,b,x,a,b,x, and yyy be real variables satisfying the system of equations above.
Find the value of ax5+by5ax^5+by^5 ax5+by5.
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