\({\bf A: }\)

\({\bf B: }\)

Given the curve \({\bf 16 x^2 - 24 xy + 9 y^2 - 15 x - 20 y = 0 }\) and the perpendicular lines \({\bf x - 7 y + 10 = 0 \: and \: 7 x + y - 10 = 0 }\) in graph \({\bf (A) \:, }\) find the area in graph \({\bf (B) }\) consisting of three right triangles. \(\)

Note: Although, the area is independent of the curve

\({\bf 16 x^2 - 24 xy + 9 y^2 - 15 x - 20 y = 0 \:,}\) the curve is needed to find the points of intersection of the curve and the given lines.
\(\)

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