A problem by Nazmus Sakib

Algebra Level 1

True or False:

24+212112+121Z\frac{24 + 2 \sqrt{121}}{12 + \sqrt{121}} \in \mathbb{Z}

Note: By breaking ,\sqrt, if you want to change the sign then the sign of the numerator and denominator should be the same. e.g a+b2c+d2=a+bc+d\dfrac{a+\sqrt{b^2}}{c+\sqrt{d^2}} = \dfrac{a+b}{c+d} or abcd\dfrac{a-b}{c-d}

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