# A problem by Nazmus Sakib

Algebra Level 1

True or False:

$\frac{24 + 2 \sqrt{121}}{12 + \sqrt{121}} \in \mathbb{Z}$

Note: By breaking $\sqrt,$ if you want to change the sign then the sign of the numerator and denominator should be the same. e.g $\dfrac{a+\sqrt{b^2}}{c+\sqrt{d^2}} = \dfrac{a+b}{c+d}$ or $\dfrac{a-b}{c-d}$

×